@b4n commented on this pull request.
- if (source_file->lang == TM_PARSER_C || source_file->lang == TM_PARSER_CPP)
+ { + const gchar **ext; + const gchar *common_src_exts[] = + {".c", ".C", ".cc", ".cp", ".cpp", ".cxx", ".c++", ".CPP", ".CXX", NULL}; + + for (ext = common_src_exts; *ext; ext++) + { + if (g_str_has_suffix(source_file->short_name, *ext)) + { + source_file->is_c_source = TRUE; + break; + } + } + } +
Yes, we could do that - makes probably more sense as the `is_source` flag is valid for all languages and not specific to C/C++.
Yeah, the main reason I suggest this would be to make the `init_tag()` check simply `tag->local = tag_entry->isFileScope && file->is_source` rather than having language-specific tests there as well.
Does this code offer any benefit compared to what I wrote? I personally find my code a bit easier to read as you avoid the extra branch where `.` is not found
Merely premature optimization (comparison only compares useful things, and traverse the basename only once), so no, it doesn't really matter.
If it's only a readability issue, you could easily rewrite this ever so slightly like so: ```C source_file->is_source = TRUE;
if (source_file->lang == TM_PARSER_C || source_file->lang == TM_PARSER_CPP) { const gchar *ext = strrchr(source_file->short_name, '.');
source_file->is_source = FALSE; if (ext) { const gchar *common_src_exts[] = {"c", "C", "cc", "cp", "cpp", "cxx", "c++", "CPP", "CXX"};
for (int i = 0; i < G_N_ELEMENTS(common_src_exts); i++) { if (strcmp(ext + 1, common_src_exts[i]) == 0) { source_file->is_source = TRUE; break; } } } } ```
anyway, either way is fine.