parenthesized initializers are highlighted and they probably should not

@b4n, Good catch, another place the syntax is used for something else, ahh C++ :)

operators is not highlighted as functions.

@linvinus I'm not sure you understood the point, in C++ the call operator () can be overloaded and applied to objects, not just to functions. Your image doesn't show that case. As @b4n says it depends if you want all callables highlighted, or functions.

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